0=25y^2-36y

Solution for 0=25y^2-36y equation:

0=25y^2-36y

We move all terms to the left:

0-(25y^2-36y)=0

We add all the numbers together, and all the variables

-(25y^2-36y)=0

We get rid of parentheses

-25y^2+36y=0

a = -25; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·(-25)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*-25}=\frac{-72}{-50}
=1+11/25
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*-25}=\frac{0}{-50}
=0
$